640-10x^2=0

Solution for 640-10x^2=0 equation:

640-10x^2=0

a = -10; b = 0; c = +640;
Δ = b2-4ac
Δ = 02-4·(-10)·640
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*-10}=\frac{-160}{-20}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*-10}=\frac{160}{-20}
=-8
$